Tea "Labouchere roulette system" and the System of "Half a dozen."

The essence of the Labouchere Roulette System method in the following:

1. You will use the game in equal opportunities: black-red, even-odd and the like.

2. At the beginning of the game, you need to create a random sequence of numbers from 1 to 9. Optimally, if the number is 4-6 (for example, our number can be 4-1-7-3).

3. Rate determined by folding the extreme numbers of our range (in our case it is four 3=7).

4. If you win, the final numbers are removed (we have 1-7). If the series is over, create a new list.

5. In case of a loss, you need to add a number of a number equal to a lost bet (we have a 7, and a number will look like this: 4-1-7-3-7, so the next bet is 4 7 =11).

There is also a “Reverse Labouchere”. In this case, when the win is added to the last bid and if you lose, you cross out the extreme numbers of a number.

The system of “Three by three twists”.

How to win at roulette, following this strategy? Much easier and faster than in previous versions. The idea is to make three bets per roll. The series is three games back.

The probability that you can win at roulette in this way is very large, but also the minimum bet has a higher size – a multiple of 17. You need to put the ratio 9: 6: 2 for the following positions:

9 units – “minus”;

6 units on the third dozen;

2 units in the corners numbers 19, 20,22, 23 or 20, 21, 22, 24.

In this case, when the rate is 17 the prize will be – 18. In one spin you can win one unit (at the rate of 17 to 1, at the rate of 34 – 2). Losing in this scenario is also possible: if you roll the zero or the number 21 and 24 (depending on the corner).

The odds of winning in this game are very high, much higher than using the three previous methods. All these systems you can try at http://www.topcasinosnz.com/ with their no deposit bonus system will be free.

The “Half Dozen” system.

The essence of the method in the following:

expect to see the non-winning numbers 19, 20, 21, 22, 23, and 24;

skip a turn;

make even bets on a smaller number and the third dozen;

at lossless we will refund your stake if you get half the return rate on the third dozen;

after winning, continue to wait for the numbers that fall from paragraph 1, when you lose – increase the rate by the martingale method.

It is worth noting that when you reach “zero”, the player loses his bet.

The system is “31”.

This is the most convenient game in equal opportunity betting. How to beat casino roulette in this way? You have to follow the instructions:

1. Starting Bid: 1 to even the odds.

2. In the case of gain, increase it twice.

3. In case of increasing speed loss of progression 1-1-1-2-2-4-4-8-8. If we win the twist, let’s go back to the beginning.

The minimum amount of money for this game method – $ 31. This amount will allow us to withstand ten losing spins. It should be noted that this is quite unlikely, but also possible.

If you win twice in a row, you must return to the initial bet. It will reduce the risk of losing all the money in roulette. After winning, generate the excitement and false confidence that luck is on your side.

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